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Is there a mathematical function for this?
show user profile  Mr_Stabby
Im way off the deep end with this analytical algorithm im building, my gut told me the problem is solvable so i just followed the seemingly random pile of numbers until i found some order. My crazies aside is there a math function that would turn 5 into 5+4+3+2+1=15, 4 into 4+3+2+1=10? Sorta like ! except with + instead of *

read 668 times
8/31/2012 2:48:58 AM (last edit: 8/31/2012 2:48:58 AM)
show user profile  jareu
Yes there is, I can't remember if it is dot product or a variation of dot product which does what you want but I'll look up summation in a min and see what I can find for ya



He who says it cannot be done is interrupting the man doing it.

read 659 times
8/31/2012 3:24:59 AM (last edit: 8/31/2012 3:53:29 AM)
show user profile  gogodr
n(n+1)/2
5*6/2 = 15
4*5/2 = 10

Hello there

beautiful ;3


read 654 times
8/31/2012 3:38:18 AM (last edit: 8/31/2012 3:40:06 AM)
show user profile  jareu
ok forget dot product, I was confusing vector math for a minute.


edit: yeah use gogodr's function, I forgot about that one :)



He who says it cannot be done is interrupting the man doing it.

read 645 times
8/31/2012 3:46:47 AM (last edit: 8/31/2012 3:53:17 AM)
show user profile  Mr_Stabby
gogodr - oh ya! *flashback to high school* that'll cut down the execution time, thanks.

jaeru - int lvl(int n) {int v = 0; for (int i = 0; i < n; i++) {v += i;} return v;} that was my current one, even though it looks nice on paper not very efficient :|

read 643 times
8/31/2012 3:48:00 AM (last edit: 8/31/2012 3:49:10 AM)
show user profile  herfst1
Hey, didn't some French kid work that out when he was asked to do it from 100 as a way for the teacher to get 30 mins peace? Think he was sent to detention for being a smart ass before they worked out that he was a genius.

Or I could be mistaken.
read 605 times
8/31/2012 10:52:25 AM (last edit: 8/31/2012 10:52:25 AM)
show user profile  Garp
Stabby, care to share a little about what it is you're doing?




read 595 times
8/31/2012 11:35:31 AM (last edit: 8/31/2012 11:35:31 AM)
show user profile  Mr_Stabby
trying to extrapolate an array of values that follow unknown amount of unknown but mathematically definable trajectories

read 576 times
8/31/2012 8:37:11 PM (last edit: 8/31/2012 8:37:11 PM)
show user profile  advance-software


I reckon stabby's working on a new way of preventing side fumbling.
read 571 times
8/31/2012 8:45:40 PM (last edit: 8/31/2012 8:48:54 PM)
show user profile  Garp
So if you walk on a landmine, you want to know where all your bits are going to fall?
You need to factor in the wind.




read 558 times
8/31/2012 9:10:50 PM (last edit: 8/31/2012 9:10:50 PM)
show user profile  Mr_Stabby
Its not for anything specifically, just curiosity mostly. The theory is that if i could observe the coordinates of a tea leaf in relation to the center of the galaxy cluster over X samples then a) when the algorithm starts producing 0's at the top of its hierarchial tree then i have all the data i need and the level where it produces the 0's will be X which is the number of mathematically definable trajectories that are affecting it b) the first member of each array in the tree will be the velocity/energy or whatever im measuring representation of the effect on the tea leaf. In short it creates a series of numbers that when extrapolated define the entire galaxy cluster in relation to the tea leaf.

read 529 times
8/31/2012 11:22:31 PM (last edit: 8/31/2012 11:22:31 PM)
show user profile  advance-software

read 522 times
8/31/2012 11:32:23 PM (last edit: 8/31/2012 11:32:23 PM)
show user profile  Garp
Hmm.
Aren't you afraid that X might be larger than the total number of particles in the Universe?




read 517 times
8/31/2012 11:40:00 PM (last edit: 8/31/2012 11:40:00 PM)
show user profile  Mr_Stabby
quite possibly is, a more practical example would be using it as a smoothing function - you draw a line, it places x number of points on the line at equal distance and recreates the line with x precision. The cool thing about it is that after the sampling process which could be multicast each point can work independently while holding the pattern of the whole within itself - perfect for gpu computing stuff!

read 512 times
8/31/2012 11:48:14 PM (last edit: 8/31/2012 11:48:14 PM)
show user profile  Mr_Stabby
Anybody like retarded math puzzles?

5 6 4 -> 5 4 2
2 4 6 -> 2 1 3
5 13 10 -> 5 8 5
8 10 6 -> 8 7 3
3 7 8 -> 3 3 4
3 8 8 -> 3 4 4
3 9 8 -> 3 5 4


i know how to get from the right side to the left side, the question is how do i get from the left to the right

EDIT: fixed typo in values.. which was also on my set.. which suddenly makes it simple

a' = a
c' = c/2
b' = b + c' - c

read 492 times
9/1/2012 2:27:53 AM (last edit: 9/1/2012 2:58:03 AM)
 
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